151. Reverse Words in a String ๐Ÿ”„

Difficulty: Medium - Tags: String, Two Pointers

LeetCode Problem Link

Description

Given an input string s, reverse the order of the words.

A word is defined as a sequence of non-space characters. The words in s will be separated by at least one space.

Return a string of the words in reverse order concatenated by a single space.

Note that s may contain leading or trailing spaces or multiple spaces between two words. The returned string should only have a single space separating the words. Do not include any extra spaces.

Examples

Example 1:

Input:

s = "the sky is blue"

Output:

"blue is sky the"

Example 2:

Input:

s = "  hello world  "

Output:

"world hello"

Explanation: Your reversed string should not contain leading or trailing spaces.

Example 3:

Input:

s = "a good   example"

Output:

"example good a"

Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string.

Constraints

  • The input string s contains only printable ASCII characters.

  • s does not contain any leading or trailing spaces.

  • The words in s will be separated by a single space.

Solution ๐Ÿ’ก

To solve this problem, we can split the string into words, remove any extra spaces, and reverse the list of words. Finally, we join them back into a string with a single space separating the words.

Java

class Solution {
    public String reverseWords(String s) {
        // Trim the string and split by spaces
        String[] words = s.trim().split("\\s+");
        // Initialize a StringBuilder to store the reversed words
        StringBuilder reversed = new StringBuilder();
        
        // Traverse the words array in reverse order and append them to the StringBuilder
        for (int i = words.length - 1; i >= 0; i--) {
            reversed.append(words[i]);
            if (i > 0) {
                reversed.append(" ");
            }
        }
        
        // Convert StringBuilder back to String
        return reversed.toString();
    }
}

Time Complexity โณ

  • O(n): The time complexity is linear, where n is the length of the input string.

Space Complexity ๐Ÿ’พ

  • O(n): The space complexity is also linear, as we are storing the reversed words in a new string.

You can find the full solution here.

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